would 190 km of pipe make really dense tangle in a space the size of a small warehouse? the diameter of the pipes seem to be pretty random up to 1m according to the entry
Yeah I guess the diameter is the key detail. I went on a little rabbit hole with this, feel free to ignore it. TLDR I tried different diameters in the meter-to-cm range mentioned by the article, and the total length varied by a factor of a million.
First I tried calculating for a fixed diameter throughout.
If I start with a warehouse volume and a total pipe length, and then work backwards, I get a wide but reasonable pipe diameter. For example, if the warehouse is around 80,000 cubic meters (maybe 100x100x8?), and 40,000 of that is pipe, then the typical pipe diameter is around sqrt(40000 / (π * 190000)) * 2 ≈ 0.52 m wide.
But the SCP entry says some pipes are as narrow as 2.5 cm. Total length explodes as diameter shrinks. One example is the human body. We have around 100,000 km of blood vessels in our bodies, with a typical diameter of around 0.008 cm and a total volume of around 5 liters (0.005 cubic meters). If we scale 0.005 up to 40,000 cubic meters of pipe in a warehouse, a 1:200 length scaling, the typical diameter would be around 1.6 cm, and the total length would be 200 million km, if SCP 015 is biased toward a lot of little “capillaries.”
I drank too much caffeine, so next I calculated total length for a distribution of diameters.
Shit, it wouldn’t be inverse with diameter, it would be inverse with cross-sectional area. I gotta redo this lol
If the distribution of diameters is inverse, meaning there’s twice as much 10 cm-wide pipe as 20 cm, and twice as much 5 cm as 10 cm, and so on, then we can integrate over diameter, over the stated range of 2.5 cm to 1 m. An inverse curve would have the form y=a/x, where a is a constant, x is diameter, and y is length of pipe at that diameter. If the total length is 190 km, we can set the integral equal to 190 km and then solve for a:
(hopefully my math isn’t shit)
Then plug in a to integrate the volume, which is just the product of cross-sectional area π(x/2)^2 and length:
…So, unless I fucked up my math, which is pretty likely, it actually works out to a somewhat warehouse-sized volume of around 20,000 cubic meters. I don’t know if an inverse distribution is a valid assumption though.
Just put pipes everywhere, one of them is bound to make sense. Yeah put a pipe from one non functional corner of the sink to another. Fuck it
Sorry if it looks like it doesn’t make sense to you but actually this is a stunning example of the yoshitaka amano school of plumbing design
I hope you’re paid by the hour or by the pipe because there’s actually even more pipes than it looks like
it’s cool it’s just SCP-015
Surprisingly not much pipe. An oil refinery can contain over 1000 km of pipes
https://elsegundo.chevron.com/what-we-do
would 190 km of pipe make really dense tangle in a space the size of a small warehouse? the diameter of the pipes seem to be pretty random up to 1m according to the entry
Yeah I guess the diameter is the key detail. I went on a little rabbit hole with this, feel free to ignore it. TLDR I tried different diameters in the meter-to-cm range mentioned by the article, and the total length varied by a factor of a million.
First I tried calculating for a fixed diameter throughout.
If I start with a warehouse volume and a total pipe length, and then work backwards, I get a wide but reasonable pipe diameter. For example, if the warehouse is around 80,000 cubic meters (maybe 100x100x8?), and 40,000 of that is pipe, then the typical pipe diameter is around sqrt(40000 / (π * 190000)) * 2 ≈ 0.52 m wide.
But the SCP entry says some pipes are as narrow as 2.5 cm. Total length explodes as diameter shrinks. One example is the human body. We have around 100,000 km of blood vessels in our bodies, with a typical diameter of around 0.008 cm and a total volume of around 5 liters (0.005 cubic meters). If we scale 0.005 up to 40,000 cubic meters of pipe in a warehouse, a 1:200 length scaling, the typical diameter would be around 1.6 cm, and the total length would be 200 million km, if SCP 015 is biased toward a lot of little “capillaries.”
I drank too much caffeine, so next I calculated total length for a distribution of diameters.
Shit, it wouldn’t be inverse with diameter, it would be inverse with cross-sectional area. I gotta redo this lol
If the distribution of diameters is inverse, meaning there’s twice as much 10 cm-wide pipe as 20 cm, and twice as much 5 cm as 10 cm, and so on, then we can integrate over diameter, over the stated range of 2.5 cm to 1 m. An inverse curve would have the form y=a/x, where a is a constant, x is diameter, and y is length of pipe at that diameter. If the total length is 190 km, we can set the integral equal to 190 km and then solve for a:(hopefully my math isn’t shit)Then plug in a to integrate the volume, which is just the product of cross-sectional area π(x/2)^2 and length:…So, unless I fucked up my math, which is pretty likely, it actually works out to a somewhat warehouse-sized volume of around 20,000 cubic meters. I don’t know if an inverse distribution is a valid assumption though.