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8 months agoYou can see the awful, misaligned panel gaps in those photos.
You can see the awful, misaligned panel gaps in those photos.
Nice find!
I’d be curious to see RTINGS do a review of the panel on it.
Except if you care about anything having to do with picture quality, brightness, contrast ratio or features such as HDR etc, then it’s going to be a really shitty TV. They’re made for the menus at McDonald’s, not a device for modern media.
This is only the 3764th post this week…
At some point, the people of Afghanistan should be able to take control of their own country. How can a vast majority of the people sit there and let a tiny percentage dictate the lives and rules for everyone? Kick the Taliban out of your country.
Put it in ChatGPT, just for fun…
To find the probability of drawing 7 or more face cards (which includes Jacks, Queens, Kings, and Aces) from 8 random cards, we first need to recognize that in a standard deck of 52 cards, there are 16 face cards (4 each of Jacks, Queens, Kings, and Aces) and 36 non-face cards.
We need to calculate the probabilities of two cases:
For both, we can use the hypergeometric distribution. The general formula for the hypergeometric probability is:
[ P(X = k) = \frac{{\binom{K}{k} \binom{N-K}{n-k}}}{{\binom{N}{n}}} ]
Where:
For 7 face cards: [ P(X = 7) = \frac{{\binom{16}{7} \binom{36}{1}}}{{\binom{52}{8}}} ]
For 8 face cards: [ P(X = 8) = \frac{{\binom{16}{8} \binom{36}{0}}}{{\binom{52}{8}}} ]
We will calculate these probabilities to get the final answer.
The probability of drawing 7 or more face cards (Jacks, Queens, Kings, Aces) from 8 random playing cards is approximately 0.0564%, or about 1 in 1772. This is a rare event given the small proportion of face cards in a standard deck.